Well then.. your teacher must realise his failure, because that questin has TWO correct answers. A and B are correct. The magnets do not generate an effective force to accelerate the car, but neither do they decelerate it. The answer would therefore depend on the answer to the following question (disregarding friction):
“Was the car moving, at the time that it was last observed?”
And technically speaking, your constant velocity of 0 is only relative to an observer of the same velocity. Imagine your actual velocity while the universe is expanding, while our Sun orbits the centre of the Milky Way, and while our planet orbits the Sun (Whilst spinning!).
So technically (Due to the ambiguity), the answer is B and the velocity is not 0
On the other hand, we can’t really know if the velocity stays the same, or if it gets greater or smaller, as our planet, solar system, galaxy and everything moves. Personally, I find it improbable that the velocity is truly constant.
This is true, for starters it has already been proven that the galaxies are moving further apart at increasing speeds (Some sh*t about dark matter or something).
It doesn’t move at any velocity or acceleration. At all. Which does NOT make it “all of the above”. You’ll have to do better than “Read a physics book”.
Depends on your perspective. In my mind, if it isn’t changing, it’s constant. thus if it’s zero, as long as it stays that way, it’s constant, whatever “it” is.
Actually the car will move at a constant velocity. If that velocity is stationary (relative to the viewer frame of course) then it will stay stationary. If the velocity is not stationary, the car will move at that velocity. Of course, this changes when acted upon by any outside force including friction, other magnets, a wall, etc, as any physics equation does.
Actually, if the car was moving at a constant velocity of ‘Not moving’ then the answer ‘A’ would better encompass the question and therefore, is closer to being the right answer as stationary is generally not considered as being a velocity.
Let’s get technical and say that it will move at a constant acceleration. Acceleration is a change in velocity, being that all things on a planet are under constant acceleration as the planet both spins and orbits.
But the force of the magnets will cancel each other out.
Yes it will, the pole going over the car (which is holding the furthest magnet) has the exact same effect as an electrically charged coil around a magnet. The 2 magnets joined to the car at the opposite ends while positioned to interact creates an electromagnetic field. This field can is sensitive to the Earth’s magnetosphere which eventually accelerate the car up to a constant velocity of c towards one of the Earth’s poles (depending on direction of current).
This is true. Although the short straight sections connected to the magnet must be precisely 0.5lambda to allow for the magnet to properly hook into the resonance field within the magnetosphere.
but the (b) answer is “move at a constant velocity”. 0 is a velocity, but it is the only velocity that does not allow the car to move. To say move at a non-zero velocity is redundant.
If the car was already moving then the answer would be (c) as the car would decelerate at a roughly constant rate due to friction until it stops. While not perfect it is the best of the three choices.
If not already in motion then the car would not move as there is no apparent outside force (other than gravity on an assumed level surface) acting on the car.
I actually never understood why this wouldnt work.
If it does pull, wont the magnets run out of juice after a while? Potential and all that exhaustible stuff?
It doesn’t pull. Newton’s laws of motion state that for every action there is an equal and opposite reaction. The “pull” experienced by one magnet is canceled by the “pull” of the other. There is a net zero force, meaning nothing will change velocity.
Then it still wouldn’t work. Magnetism works in both directions: Metal gets attracted by the magnet, but the magnet is also attracted by the metal. (Or in this case: the other pole).
Increasing the strength of the right Magnet will increase its pull on the other, resulting in a greater force pushing the car towards the right. However, it will also increase the right Magnets attraction to the left Magnet, resulting in an equally large increase in force pushing the car left. Both forces are equal, perfectly cancelling each other out.
I don’t think it has anything to do with Newton’s laws. I’m not sure if these are the terms in English, but the car, rod and magnets are part of a single system and the magnetic atraction is therefore a internal force. Internal forces don’t affect a system’s momentun.
That’s the bigger part of the picture. Some people, however, don’t understand the whole “rod is attached to the car” thing, so you have to explain it differently. But yes, all that will happen is that tension will be put on the rod, and the car will sit there like a brick.
I think, if someone was actually pulling on the magnet in the front forward, the other magnet would be attracted to it, but the magnets would both have to be very strong.
Yes, but in such a case it would be the person, not the magnets, supplying the force that moves the car. It would be functionally identical to the person just grabbing the car and pulling it.
A and B are both correct if the velocity is 0 (because, as previously noted, 0 is a constant).
C is correct if the velocity is non-zero (perhaps because of an external initial force), because friction in the wheels and rolling resistance will decelerate the vehicle.
The velocity is irrelevant at C – the acceleration is change in velocity over time, so if the velocity, 0 or not, is not changing, the acceleration is constant at zero as well.
The question is a little sloppy also; any of the answers could be false given a variety of initial conditions. We however are assuming the car is stationary on a horizontal plane with no external forces, therefore all answers are true.
The car is on Earth. The Earth is spinning on its axis as it is orbiting the sun. The sun is orbiting the galaxy and all manner of mass is also affecting that path. The galaxy is headed away from the point where the ‘big bang’ happened.
The car is spiraling every which way, moving at unimaginable speeds.
And so are you.
Cue up the ‘Galaxy Song’ from ‘Monty Python & The Meaning of Life’ for lots of (generally inaccurate) numbers.
Oh, and the magnet would probably move the car a bit (backwards) if the pole broke and the magnets snapped together, but that’s about all the potential that I see.
Haha, except if that’s true, it’s probably a non-constant acceleration.
Either the question needs expansion or the answer set. If he’s really into it, he should add these answers in this order, and then there is only one correct answer:
D. None of the Above
E. Some of the Above
F. All of the Above
(And yes, in this case, “All of the Above” should follow “None of the Above” since it is part of the subset of correct answers).
Apparently everyone above failed to see the “Explain your choice” area below the multiple choice answers. I would imagine that as long as you defended the answers appropriately any one could be counted as correct.
a), if there is no intial velocity, the Force in any direction left or right of the space between the two magnets is zero, and the attractive forces between the two magnets act on the same body, with an overall nil force, ergo the net force acting on the system is zero, so no acceleration.
Unless moving at a constant velocity already, the answer is A. The attractive forces each magnet has on the other are equal in magnitude, but opposite in terms of direction of the force. With this, it can be said that, without doubt, unless the cart was already moving at a constant velocity, it would not be moving, and if it previously had a velocity, it would remain the same.
FYI 0 ms^-1 is not a velocity it is a speed because velocity must have a sign and a direction and 0 is the only real number to have a magnitude but no sign
Sure it is a velocity. There is nothing wrong with saying that you’re travelling North at 0 m/s.. There is nothing invalid with assigning a direction to a zero velocity.. Its a trivial and pointless detail but it’s still valid.
Fake.
Clearly. Why doesn’t the new cheezburger have an option to thumbs up/down or rate things now?
You have to have a Cheezburger Platinum Account©®™
4 internets for you, Glenn Coco.
Glenn Coco isn’t here…
…DIBs!!!!!!
You’re right, it’s fake because you need a BIGGER magnet in the front!
No it isn’t.
It’s definitely real, I’m in that class, it’s our AP Physics class too.
Well then.. your teacher must realise his failure, because that questin has TWO correct answers. A and B are correct. The magnets do not generate an effective force to accelerate the car, but neither do they decelerate it. The answer would therefore depend on the answer to the following question (disregarding friction):
“Was the car moving, at the time that it was last observed?”
Its definitely real because Garry’s Mod proved it was real.
Were is it written that only one answer is right?
standing stil is just moving with a constant velocity of 0.
And technically speaking, your constant velocity of 0 is only relative to an observer of the same velocity. Imagine your actual velocity while the universe is expanding, while our Sun orbits the centre of the Milky Way, and while our planet orbits the Sun (Whilst spinning!).
So technically (Due to the ambiguity), the answer is B and the velocity is not 0
Pwned
On the other hand, we can’t really know if the velocity stays the same, or if it gets greater or smaller, as our planet, solar system, galaxy and everything moves. Personally, I find it improbable that the velocity is truly constant.
This is true, for starters it has already been proven that the galaxies are moving further apart at increasing speeds (Some sh*t about dark matter or something).
You don’t get to alter the question to make it correspond to your predetermined conundrum. The question does not say to disregard friction.
If it has a constant acceleration, it doesn’t have a constant velocity… Dumbass.
if acceleration = zero, it does.
dammit, i just crapped myself again
Fake probably.
F@rst.
nope, Chuck Testa
Depends on the strength of the magnet
Can’t tell if troll or Mormon…
Really surprised it took this long for a Mormon joke.
Depends, does he live in the Scribblenauts world?
You win!
^^^^ +1 internets forever and ever and ever
All of the above. No, I won’t clarify why. Go read a physics book.
It doesn’t move at any velocity or acceleration. At all. Which does NOT make it “all of the above”. You’ll have to do better than “Read a physics book”.
Depends on your perspective. In my mind, if it isn’t changing, it’s constant. thus if it’s zero, as long as it stays that way, it’s constant, whatever “it” is.
ya, i think its safe to say that if its not changing, it is constant, so if it is zero and stays zero, its constant, so it is a, b, and c.
the forces of both magnets are equal and cancel each other out, so the car will not move
Source: Mormons
Actually the car will move at a constant velocity. If that velocity is stationary (relative to the viewer frame of course) then it will stay stationary. If the velocity is not stationary, the car will move at that velocity. Of course, this changes when acted upon by any outside force including friction, other magnets, a wall, etc, as any physics equation does.
Actually, if the car was moving at a constant velocity of ‘Not moving’ then the answer ‘A’ would better encompass the question and therefore, is closer to being the right answer as stationary is generally not considered as being a velocity.
A constant velocity of zero?
velocity is a vector meaning it must have both magnitude and direction
0 is not a magnitude
0 is an absence of magnitude
0 is a magnitude of 0.
Let’s get technical and say that it will move at a constant acceleration. Acceleration is a change in velocity, being that all things on a planet are under constant acceleration as the planet both spins and orbits.
But the force of the magnets will cancel each other out.
The acceleration caused by gravity is an external force and generally not assumed under all conditions for a physics question.
Incorrect!
A is correct for a specific condition, B is correct for all conditions (not accounting for external forces again).
Force equals zero means zero acceleration.
Thus the car will move at constant speed, you mormon.
No, it won’t, because of friction.
Yes it will, the pole going over the car (which is holding the furthest magnet) has the exact same effect as an electrically charged coil around a magnet. The 2 magnets joined to the car at the opposite ends while positioned to interact creates an electromagnetic field. This field can is sensitive to the Earth’s magnetosphere which eventually accelerate the car up to a constant velocity of c towards one of the Earth’s poles (depending on direction of current).
Friction is puny compared to these forces.
lol
This is true. Although the short straight sections connected to the magnet must be precisely 0.5lambda to allow for the magnet to properly hook into the resonance field within the magnetosphere.
Ain’t science fun?
I can see your name is truth in advertising. I commend you for your honesty.
someone try this.
Trick question, 0 is a valid velocity.
but the (b) answer is “move at a constant velocity”. 0 is a velocity, but it is the only velocity that does not allow the car to move. To say move at a non-zero velocity is redundant.
If the car was already moving then the answer would be (c) as the car would decelerate at a roughly constant rate due to friction until it stops. While not perfect it is the best of the three choices.
If not already in motion then the car would not move as there is no apparent outside force (other than gravity on an assumed level surface) acting on the car.
I actually never understood why this wouldnt work.
If it does pull, wont the magnets run out of juice after a while? Potential and all that exhaustible stuff?
It doesn’t pull. Newton’s laws of motion state that for every action there is an equal and opposite reaction. The “pull” experienced by one magnet is canceled by the “pull” of the other. There is a net zero force, meaning nothing will change velocity.
Does it depend on the size and strength of the magnets? What if there was a stronger magnet on one side.
Then it still wouldn’t work. Magnetism works in both directions: Metal gets attracted by the magnet, but the magnet is also attracted by the metal. (Or in this case: the other pole).
Increasing the strength of the right Magnet will increase its pull on the other, resulting in a greater force pushing the car towards the right. However, it will also increase the right Magnets attraction to the left Magnet, resulting in an equally large increase in force pushing the car left. Both forces are equal, perfectly cancelling each other out.
I don’t think it has anything to do with Newton’s laws. I’m not sure if these are the terms in English, but the car, rod and magnets are part of a single system and the magnetic atraction is therefore a internal force. Internal forces don’t affect a system’s momentun.
That’s the bigger part of the picture. Some people, however, don’t understand the whole “rod is attached to the car” thing, so you have to explain it differently. But yes, all that will happen is that tension will be put on the rod, and the car will sit there like a brick.
I think, if someone was actually pulling on the magnet in the front forward, the other magnet would be attracted to it, but the magnets would both have to be very strong.
Yes, but in such a case it would be the person, not the magnets, supplying the force that moves the car. It would be functionally identical to the person just grabbing the car and pulling it.
I wait for the day troll physics actually makes some labcoat shriek “Eureka!” and the world gets changed.
Troll physics are by far some of my favorite memes.
A, B, and C are all correct: the car would have a constant position, velocity, and acceleration, all of which would be zero.
A position of zero? What would that be, the centre of the Earth?
It depends of the frame of references.
According to a globe, It would be the north pole, or anything on the 0 longitude or latitude.
Alright, 0 units from the starting position.
The answer is D – all of the above.
A and B are both correct if the velocity is 0 (because, as previously noted, 0 is a constant).
C is correct if the velocity is non-zero (perhaps because of an external initial force), because friction in the wheels and rolling resistance will decelerate the vehicle.
So close;
The velocity is irrelevant at C – the acceleration is change in velocity over time, so if the velocity, 0 or not, is not changing, the acceleration is constant at zero as well.
The question is a little sloppy also; any of the answers could be false given a variety of initial conditions. We however are assuming the car is stationary on a horizontal plane with no external forces, therefore all answers are true.
Actually D is “That’ll cause an explosion the size of france.” You mean G; “A, B AND C”
the answer is none of the above, since the universe is not geocentric
Daniel, I’m sooooo happy you did this. 3/4th period physics is the best!
Wow, your school has fractional periods?
A and B if no friction, C if moving and with friction.
Answer is C. The car would keep on falling at gravitational acceleration because of the lack of the ground.
The rod cannot move. Therefore, the rod will break off of the car, and the magnet will propel the car forward.
Problem?
Yeah, now it’s broken.
Also if the magnet broke off it would fly forwards- propelling the car backwards via conservation of momentum.
The car is on Earth. The Earth is spinning on its axis as it is orbiting the sun. The sun is orbiting the galaxy and all manner of mass is also affecting that path. The galaxy is headed away from the point where the ‘big bang’ happened.
The car is spiraling every which way, moving at unimaginable speeds.
And so are you.
Cue up the ‘Galaxy Song’ from ‘Monty Python & The Meaning of Life’ for lots of (generally inaccurate) numbers.
Oh, and the magnet would probably move the car a bit (backwards) if the pole broke and the magnets snapped together, but that’s about all the potential that I see.
And where did it say the car was on Earth?
This must be one of those trick question. It’s moving so fast that it looks like it’s not moving at all.
But how are we supposed to know how magnets work? That’s not covered under physics.
The car will move at a constant velocity, unless acted upon by an outside force.
C.
Explanation: He’s a troll. He’s bound to have a motor in there to fool people. That thing will not stand still!
Haha, except if that’s true, it’s probably a non-constant acceleration.
Either the question needs expansion or the answer set. If he’s really into it, he should add these answers in this order, and then there is only one correct answer:
D. None of the Above
E. Some of the Above
F. All of the Above
(And yes, in this case, “All of the Above” should follow “None of the Above” since it is part of the subset of correct answers).
G. ???
H. Profit !!
Apparently everyone above failed to see the “Explain your choice” area below the multiple choice answers. I would imagine that as long as you defended the answers appropriately any one could be counted as correct.
a), if there is no intial velocity, the Force in any direction left or right of the space between the two magnets is zero, and the attractive forces between the two magnets act on the same body, with an overall nil force, ergo the net force acting on the system is zero, so no acceleration.
Unless moving at a constant velocity already, the answer is A. The attractive forces each magnet has on the other are equal in magnitude, but opposite in terms of direction of the force. With this, it can be said that, without doubt, unless the cart was already moving at a constant velocity, it would not be moving, and if it previously had a velocity, it would remain the same.
Anyone who argued about the validity of this question/experiment got trolled SO hard.
FYI 0 ms^-1 is not a velocity it is a speed because velocity must have a sign and a direction and 0 is the only real number to have a magnitude but no sign
Sure it is a velocity. There is nothing wrong with saying that you’re travelling North at 0 m/s.. There is nothing invalid with assigning a direction to a zero velocity.. Its a trivial and pointless detail but it’s still valid.
It’s A. The pull of the magnets cancel each other out, meaning the car does not move at all. Both B and C say that the car is moving.
B and C could both be constant values of Zero.
Answer D: ?!?!?!? PROFIT
Well duh obviously it will move
Didn’t they create a sciense section for this stuff?